[Closed] filenameFromPath in max 2010 does something weird

XP or Vista/Windows7 ?

for the many problems in recent max versions dealing with filenames (like the “JPG Map” texture bug …) i suspect the NTFS junctions to be the root of evil. Junctions are used in Vista and Windows7 to hardlink some paths in the “User” folderstructure .
Does the same thing happen if you place your project directory outside the “User” path ?
Some folder that recieves no special “treatment” by windows ?

I had the same problem and ended up using:

meditmaterials[1].diffusemap.bitmap.filename

Hope it helps, cheers.

Nail,

I also notice that it was returning some strange string.
What I end up doing was to use this function where ever I had filenameFromPath


fn returnName file = (
             theFile  = getFilenameFile file
             theExt = getFilenameType file

             return (theFile + theExt)
)

Hope it helps.

Guillermo Leal

Hi all,
the problem is related with the new asset system in max 2010 that in fact gives the well know bug of JPEG File instead of the filename. To solve the problem in the materials we can use

bitmapFileIn = meditmaterials[1].diffusemap.filename as AssetUser
    print (filenameFromPath (bitmapFileIn.getFileName())

The Assetuser has the following methods:
.[b]GetAssetId/b – This is the strange we get when trying to get the filename without casting to an AssetUser
.getFileName()
.getType()

Best regards,
Daniel

So is it definately a bug then? Good to know. Unfortunately, your method won’t work for my purposes, since by the time my function gets the string, it’s just a string, not a value inside a bitmap map. I guess I’ll just stick with the string parsing backup plan.

• Neil

Hey Neil, can’t you use the dotnet equivalents?

Edit: Here’s an example:

dnPath=dotnetclass "System.IO.Path"

dnPath.getfilename "C:\Users\Administrator\Documents\3dsmax\previews\_scene.avi"

Thanks for all the suggestions everyone, in the end I decided to go with this…

fn sLibFilenameFromPath f = 
 	(
 	filteredString = filterString f "\\"
 	if filteredString.count != 0 then return filteredString[filteredString.count]
 	else return undefined
 	)

• Neil