hi,
I was wondering how my multilistbox selection. I’m using a button to do it.
I tried this:
deleteItem pNamearr ParentRollout.parentLbx.selection
ParentRollout.parentLbx.items = pNamearr
but i’ve got this error message:
MAXScript Rollout Handler Exception: -- Runtime error: array index must be positive number, got: #{5..11}
I tried this:
res = parentRollout.parentLbx.selection
for elem in res do
(
deleteItem pNamearr elem
)
but got this error:
>> MAXScript Rollout Handler Exception: -- Runtime error: array index out of bounds: 7 <<
now i’m lost :S
btw, how is it possible to put 2 fn in one?
i would like to use this 2 fonctions for a SelectByName filter:
fn ShapeSelectionLimit = shape_filt obj = isKindOf obj shape
fn filterUnique obj = findItem pNameArr obj.name == 0
I odn’t think so, I tried the exact same thing the other day, and only one function was created. Easiest thinfg is to use 2 intermediate functions that call the main function.
For multilistboxes, the selection is a bit-array (NOT an index) in your case elements 5 to 11 are selected, so you would need to loop BACKWARDS through your array (from 11 to 5), calling deleteItem on it, then re-apply the items to the multilistbox.
If you don’t go backwards, you count up from 5 to 11, but by the time you’re halfway through deleting items (5, 6, 7, 8), you’ve already shortened the array below, say 8, so iterations 8 and above would fail, as you can’t delete element 8, 9, 10, or 11 as the array is already too short.
Make sense?
Dave
thx for your answer.
i m going to try it
I’m back again
I just continue my script and fund the answer about how to use 2 functions in 1
the original functions are:
fn PathfilterUnique obj = findItem PathNameArr obj.name == 0
fn ShapeSelectionLimit = shape_filt obj = isKindOf obj shape
and the answer is:
fn PathfilterUnique obj = ((findItem PathNameArr obj.name == 0) and ( isKindOf obj shape))
about the question; how to delete my Mlb selection; a friend fund this;
on parentDelBtn pressed do
(
index=parentRollout.parentLbx.items.count
while index > 0 do
(
temp = parentRollout.parentLbx.items
if parentRollout.parentLbx.selection[index] == true then
(
deleteItem temp index
parentRollout.parentLbx.items = temp
)
index-=1
)
)
I hope it can help some people.
Here’s another way that’s a little more optimized
-- list is the multiListBox
on bt_remove pressed do
(
items = (list.items as array)
for o = (list.items as array).count to 1 by -1 where ( findItem (list.selection as array) o ) != 0 do deleteItem items o
list.items = items
)
thx for your answer Jason ^^
Sorry for replying way after the fact
Or even shorter
list.items = for i = 1 to list.items.count where not list.selection[i] collect list.items[i]
Martijn
bedankt Martijn
Oh snapple!
pfffff
echt bedankt