im trying to find the position of one pixel in 32 hdri file that have the brightest value.. it seems that its finding the wrong one…
help :banghead:
img = selectBitMap caption:"Select a Bitmap"
HDRI_W = img.width
HDRI_H = img.height
global pixel = [0,0]
global maxval = 0
progressstart "Serching..."
(
progressupdate (y as float /HDRI_H *100)
row = getpixels img [0,y] HDRI_W linear:false
for x = 1 to row.count
do
(
pixelValue = row[x].v
if pixelValue > maxval do
(
pixel = [x-1,y]
maxval = pixelValue
)
)
)
progressend ()
close img
messagebox ((img.width as string) +"
"+ (img.height as string) +"
"+
(pixel.x as string) +"
"+ ( pixel.y as string)+"
"+(maxval as string))
Did you forget your Y loop?
Yes rotem i forgot the y loop but it`s still no finding the right one…
why do you add the 0.3 0.59 0.11 to the rgb?
row = for pix in pixel_line collect
(0.3*pix.r + 0.59*pix.g + 0.11*pix.b)
See this article:
https://en.wikipedia.org/wiki/Grayscale
“In the Y’UV and Y’IQ models used by PAL and NTSC, the rec601 luma (Y’) component is computed as Y’=0.299R’+0.587G’+0.114B’.
The ITU-R BT.709 standard used for HDTV developed by the ATSC uses different color coefficients, computing the luma component as Y’=0.2126R’+0.7152G’+0.0722B’.”
Thanx Andres now i know:)
Is there a deference between pixel RGB and PixelValue
row = for pix in pixel_line collect
(0.3*pix.r + 0.59*pix.g + 0.11*pix.b)
and
row = getpixels img [0,y] HDRI_W
for x = 1 to row.count
do
(
pixelValue = row[x].v
if pixelValue > maxval do
(
If my goal is to work with 32 bit file and find the brightest pixel?