[Closed] Multiple Arrays -> Multidimensional Array

Can you use a struct?

have a look in the MXS help.

J.

append theArray_all #(theArray1[i], theArray2[i], theArray3[i])

?

Hi cubecube,
is this what you’re looking for?

theArray1 = #(diffuse,alpha,background) --#(diffuse,alpha,background,etc,etc...)
theArray2 = #(true,false,true)          --#(true,false,true,etc,etc...)
theArray3 = #("name1","name2","name3")  --#("name1","name2","name3",etc,etc...)

-- Number of arrays to process 
iNumArray = 3

-- Number of elements per array assuming all arrays have the same dimension
iNumElemPerArray = theArray1.count

-- If arrays have a smart name with a fixed part and a progressive number,
-- the code can be a little automated:

-- Initialize the array holder
theArray_all = for i = 1 to iNumElemPerArray collect #()

for i = 1 to iNumElemPerArray do
(
    for j = 1 to iNumArray do
    (
        append theArray_all[i] (execute("theArray" + (j as String)))[i]
    )
)
format "Automatic: %
" theArray_all

-- Otherwise, if names cannot be handled:

-- Initialize the array holder
theArray_all = for i = 1 to iNumElemPerArray collect #()

for i = 1 to iNumElemPerArray do
(
    append theArray_all[i] theArray1[i]
    append theArray_all[i] theArray2[i]
    append theArray_all[i] theArray3[i]
)
format "Manual:    %
" theArray_all

• Enrico

Overcomplicating?

append theArray_all theArray1
  append theArray_all theArray2 
  append theArray_all theArray3

will give you exactly what you expected.

Thanks for many reply.
My problem was solved with “collect”.

Many thanks!!:love: