[Closed] Apply same FFD modifier to different meshs ,but different orientations happen

You need to set the transform of the FFD in both to be what you need.

I would have to look at the FFD to be exact and I can’t at the moment but something like

for x in selection do x.modifiers[1].gizmo.transform=matrix3 1

Here is the test scene for this case. (in 3dsMax)
One Sphere (Mesh1) exactly placed at the Sphere part of Mesh2.
After i applyed FFD on Mesh2, i want the Mesh1 undergo the same FFD with Mesh1.
Which means the result will be exactly the same as “selecting both meshes and applying single FFD on them”.

I have try the following step but still fail to get what i want.

1. run “$Mesh1.pivot=$Mesh2.pivot”
2. run “$Mesh1.transform=$Mesh2.transform”
3. perform FFD4x4x4 on Mesh2
4. run “addModifier $Mesh1 $Mesh2.modifiers[1];”

Please help
thx

It appears that the components need to have the same transform in order to share a FFD modifier.

            One way to do it is to transform the verts in mesh1 so that we can set its transform to mesh2's and have everything look the same. 

deltaMat = $Mesh1.transform * (inverse $Mesh2.transform)
   
   convertToMesh $mesh1
   for v = 1 to $mesh1.numverts do
   (
     setVert $mesh1 v ((getVert $mesh1 v) * deltaMat)
   )
   
   $mesh1.transform = $Mesh2.transform
   
   m = FFD_4x4x4()
   
   addModifier $mesh1 m
   addModifier $mesh2 m

I thought you wanted one modifier instanced onto two objects (that’s why you see two cages each scaled to fix a mesh)

If you want one modifier displayed you can use a group:

max modify mode
    
    m2mat = $mesh2.transform
    
    g = group #($mesh1,$mesh2)
    
    -- Save the group transform
    savemat = g.transform
    
    -- Orient the group so that mesh2 is at the origin
    g.transform = inverse m2mat
    
    -- Add an FFD to the group (aligned with mesh2)
    select g
    modPanel.addModToSelection (FFD_4x4x4 ()) 
    
    -- restore the group orientation	
    g.transform = savemat
    	
 ungroup g
 
    

[EDIT: I missed the ‘ungroup’ on the last line]