[Closed] Adopt max file to folder name ??

If i have well understood this is your hierarchy :

  C:\RootFolder
           ......FolderA\
                      ............Work.max
           ......FolderB\
        ............Work.max
           ......FolderC\
                      ............Work.max
  
  and you want to convert that into : 
  
  C:\RootFolder
           ......FolderA\
                ............FolderA.max
           ......FolderB\
                ............FolderB.max
           ......FolderC\
        ............FolderC.max
  
  
  To do that, you could use this script :

(
     	-- Put your root folder here
     	RootFolder = "C:\\RootFolder\\"
     	-- This will get all the directories contained in the root folder and put them into an array :
     	folders = getDirectories (RootFolder+"*")
     	
     	-- Now Loop into the array
     	for f in folders do (
     		-- Get the FolderName, without the total path.
     		foldername = substring f (RootFolder.count+1) (f.count - (RootFolder.count+1))
     		-- Get the files contained in the folder
     		files = getFiles (f+"\\*.max")
     			
     		-- Check if there is only one max file in that folder.
     		if files.count==1 then (
     			-- Create the new FileName (With the path included)
     			newFileName = f+foldername+".max"
     			-- Rename the file
     			renameFile files[1] newFileName
     		)
     	)
     )

Use it at your own risks, be careful because it renames files !

You must replace the RootFolder and have the same hierarchy as in my example.
Also there must be only one maxfile in the folder.

many thanks floatin_

very nice coding,

i didnt tested though,

but very happy in getting a reply with coding…

Super and excellent coding, , works very good…

its as exactly as i want

thank you.

you are welcome;)

this script i tried like getting files from a single folder,

its opening a pair of files only, its not going for third file, why,

i feel i have to make something like making an increment on the loadmax files array selection of files in that folder…

if files.count>1 then (
files = getFiles (maxfilepath+”*.max”)
loadmaxfile files[1]
CurrentFileIndex = finditem files (maxfilepath+maxfilename)
LoadMaxFile files[CurrentFileIndex+1]
)